P(x)=2x^2+3x+4

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Solution for P(x)=2x^2+3x+4 equation: 



(P)=2P^2+3P+4

We move all terms to the left:

(P)-(2P^2+3P+4)=0

We get rid of parentheses

-2P^2+P-3P-4=0

We add all the numbers together, and all the variables

-2P^2-2P-4=0

a = -2; b = -2; c = -4;
Δ = b2-4ac
Δ = -22-4·(-2)·(-4)
Δ = -28
Delta is less than zero, so there is no solution for the equation

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